On the Subject of Tungsten Refinment

So I did some Calculations and I might be wrong but in the Process of breaking down Tungsten tri-oxide plus 6 Hydrogen Gas into Tungsten Dust plus 9 buckets of water, the following equation looks like:
6H^2+4WO^3==Mixing==>W+9H^2O.
Where does the extra 6 hydrogen come from to form the extra water and where did the 3 other Tungsten go? I could be completely Off my rocker and if someone can help me figure this conundrum out if I am wrong I would be very happy because at it stands in my view, I am loosing alot more tungsten then What makes sence.

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2 H + 1 O = 3 H2O, so 2 + 1 = 3.

So 6 H + 4 WO3 = 1 W + 9 H2O. so 6 + 4 = 1 + 9 = 10

Simple Maths based on Unit amounts and not mass or Volume.

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Oh thats what i was missing, thanks.

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